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0.44x^2-0.55x+0.11=0
a = 0.44; b = -0.55; c = +0.11;
Δ = b2-4ac
Δ = -0.552-4·0.44·0.11
Δ = 0.1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.55)-\sqrt{0.1089}}{2*0.44}=\frac{0.55-\sqrt{0.1089}}{0.88} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.55)+\sqrt{0.1089}}{2*0.44}=\frac{0.55+\sqrt{0.1089}}{0.88} $
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